Quote:
Originally Posted by Witchdoctor
Hmmm,,,,,,,,,,,,
Edit:
Sorry Rich, the res is passive
think about it and you will see what I mean
Picture a bucket of water with no lid, as long as the water level is above the intake and outtake it remains passive
I do understand what your though process is here, one could argue the loop would drain onto the res, and even overflow it, but with the lack of air behind it gravity is just an idea.
Example.
Take a straw, dip it into your soda, when you pull it out their is no soda in the straw, leaving density out of the equation.
Now if you put your finger over the end of a straw and pull it out the gravitaional pressure measured at 14PSI and change is not present, hence you see the soda is still in the straw & you can get a nice cold drink with out picking up the glass ......
Not sure if this makes any sense at all though and I may just be babeling ............ 
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Love you witchy. But I disagree. I am not worried about the top rad bleeding out although.. you totally made an awesome point there I totally missed, you are right, air bubbles will become a major issue in that setup. Now I am worried about it
It seems so obvious maybe you are overlooking it? Maybe it is me? I dont know.
I do not have WC stuff laying around to show you why it wont work.
I can tell you this. low power DC Pumps do not like resistance. that is a high resistance setup (not because of the rad/block config although that is true too) the slightest leak in that loop drops pressure enormously because the pumps are not pushing water through the loop they are pressurizing the resevoirs and the "passive" res are pushing water through the loop.
Crack a cap on the res, the PC over heats and shuts down, probably not before the res bubbles over though and short circuits something.
Could you imagine trying to circulate water in a pool by sucking water off the top and shooting it up through the bottom? (Of course in this example we would need a separate pump to be sucking water off the top because there is no pressure being generated just a lot of bubbles).
No of course not that is an open loop system. the PC system is closed loop and does not matter.
I get your point, (the weight of the water in the loop keeps the pump primed), I think you are missing mine, in that, my making the resevoir an active device you are required to increase pressure to the point of air pushing the water through the hoses instead of the water. since water does not compress, you are adding a resevoir for no reason at all. You cant bleed the loop because as soon as you crack a seal the air pressure drops and the water stops flowing.
EDIT: huh?